PRB: You Receive a System.InvalidOperationException Error Message While You Serialize an Object That Has Two Arrays That Both Have Unqualified Items as Public Members (816224)

MORE INFORMATION

Steps to Reproduce the Behavior

1. Start Microsoft Visual Studio .NET.
2. On the File menu, point to New, and then click Project.
3. Select either Visual C# .NET or Visual Basic .NET under Project Types. Select Console Application under Templates.
4. Name the project MyConsoleApplication, and then click OK.
5. Replace the existing code with the following code (either Visual C# .NET or Visual Basic .NET as appropriate):
   
   Visual C# .NET Code

   using System.Diagnostics;
   using System.Xml.Serialization;
   using System;
   using System.ComponentModel;
   
   public class MainClass 
   {
      static void Main() 
      {
         ClassToBeSerialized myTestObj = new ClassToBeSerialized();
         XmlSerializer mySerializer = new XmlSerializer(typeof(ClassToBeSerialized));
         mySerializer.Serialize(Console.Out, myTestObj);
         Console.Read();
      }
   }
   
   [System.Xml.Serialization.XmlTypeAttribute(Namespace="http://kbarticles.com/")]
   public class FirstClass 
   {
      public string strMem;
      public int intMem;
   }
   
   [System.Xml.Serialization.XmlTypeAttribute(Namespace="http://kbarticles.com/")]
   public class SecondClass 
   {
      public string strMem;
      public int intMem;
   }
   
   // The object of this class is used for serialization.
   public class ClassToBeSerialized 
   {
      [XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
      [XmlArrayItemAttribute("item", Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)]
      public FirstClass[] firstArrayObj = new FirstClass[2] {new FirstClass(), new FirstClass()};
   
      [XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified )]
      [XmlArrayItemAttribute("item", Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)]
      public SecondClass[] secondArrayObj = new SecondClass[2] {new SecondClass(), new SecondClass()};
   }
   

   Visual Basic .NET Code

   Imports System.Diagnostics
   Imports System.Xml.Serialization
   Imports System
   Imports System.ComponentModel
   
   ' The object of this class is used for serialization.
   Public Class ClassToBeSerialized
      <XmlArrayAttribute(Form:=System.Xml.Schema.XmlSchemaForm.Unqualified), _
      XmlArrayItemAttribute("item", Form:=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable:=False)> _
      Public firstArrayObj As FirstClass() = New FirstClass() {New FirstClass(), New FirstClass()}
   
      <XmlArrayAttribute(Form:=System.Xml.Schema.XmlSchemaForm.Unqualified), _
      XmlArrayItemAttribute("item", Form:=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable:=False)> _
      Public secondArrayObj As SecondClass() = New SecondClass() {New SecondClass(), New SecondClass()}
   
   End Class
   
   <System.Xml.Serialization.XmlTypeAttribute(Namespace:="http://kbarticles.com/")> _
   Public Class FirstClass
      Public strMem As String
      Public intMem As Integer
   End Class
   
   <System.Xml.Serialization.XmlTypeAttribute(Namespace:="http://kbarticles.com/")> _
   Public Class SecondClass
      Public strMem As String
      Public intMem As Integer
   End Class
   
   Module MyTestModule
   
      Sub Main()
         Dim myTestObj As New ClassToBeSerialized()
         Dim mySerializer As New XmlSerializer(GetType(ClassToBeSerialized))
         mySerializer.Serialize(Console.Out, myTestObj) ' Serializing the object
         Console.ReadLine()
      End Sub
   
   End Module
   

6. In Visual Studio .NET Solution Explorer, right-click MyConsoleApplication, and then click Add Reference.
7. On the .NET tab, click System.Web.Services.dll, click Select, and then click OK.
8. On the Debug menu, click Start.
   
   You receive the exception that is described in the "Symptoms" section.
9. Replace the code for the ClassToBeSerialized class with the code that is described in the "Workaround" section, and then restart the application.