Windows NT Muldiv() Function Returns Incorrect Value (159093)
The information in this article applies to:
- Microsoft Windows NT Workstation 4.0
- Microsoft Windows NT Server 4.0
This article was previously published under Q159093 SYMPTOMS
Muldiv(0,0,-1) returns -1 when it should be 0. The MulDiv function
multiplies two 32-bit values and then divides the 64-bit result by a third
32-bit value. The return value is rounded up or down to the nearest
integer.
int MulDiv(
int nNumber, // 32-bit signed multiplicand
int nNumerator, // 32-bit signed multiplier
int nDenominator // 32-bit signed divisor
Parameters
nNumber: Specifies the multiplicand.
nNumerator: Specifies the multiplie
nDenominator: Specifies the number by which the result of the multiplication
(nNumber * nNumerator) is to be divided.
Return Values
If the function succeeds, the return value is the result of the
multiplication and division. If either an overflow occurred or nDenominator
was 0, the return value is -1.
CAUSE
The multiplier is positive, the multiplicand is positive, the divisor is
negative. The result is negative when actually, the result was positive
(0).
STATUS
Microsoft has confirmed this to be a problem in Microsoft Windows NT
version 4.0.
This problem was corrected in the latest Microsoft Windows NT 4.0 U.S.
Service Pack. For information on obtaining the service pack, query on the
following word in the Microsoft Knowledge Base (without the spaces):
| Modification Type: | Major | Last Reviewed: | 8/9/2001 |
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| Keywords: | kbenv KB159093 |
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